Files
ladybird/Libraries/LibJS/Heap/Cell.h
Luke Wilde babfd70ca7 LibGC: Enforce that a Cell type must declare the allocator to use
This ensures that we are explicitly declaring the allocator to use when
allocating a cell(-inheriting) type, instead of silently falling back
to size-based allocation.

Since this is done in allocate_cell, this will only be detected for
types that are actively being allocated. However, since that means
they're _not_ being allocated, that means it's safe to not declare
an allocator to use for those. For example, the base TypedArray<T>,
which is never directly allocated and only the defined specializations
are ever allocated.
2026-01-20 12:00:11 +01:00

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C++

/*
* Copyright (c) 2020-2024, Andreas Kling <andreas@ladybird.org>
*
* SPDX-License-Identifier: BSD-2-Clause
*/
#pragma once
#include <LibGC/Cell.h>
#include <LibGC/CellAllocator.h>
#include <LibJS/Export.h>
#include <LibJS/Forward.h>
namespace JS {
class JS_API Cell : public GC::Cell {
GC_CELL(Cell, GC::Cell);
public:
virtual void initialize(Realm&);
virtual bool is_generator_result() const { return false; }
virtual bool is_environment() const { return false; }
ALWAYS_INLINE VM& vm() const;
template<typename T>
bool fast_is() const = delete;
};
}