Files
ladybird/Libraries/LibWeb/Layout/SVGBox.h
Luke Wilde babfd70ca7 LibGC: Enforce that a Cell type must declare the allocator to use
This ensures that we are explicitly declaring the allocator to use when
allocating a cell(-inheriting) type, instead of silently falling back
to size-based allocation.

Since this is done in allocate_cell, this will only be detected for
types that are actively being allocated. However, since that means
they're _not_ being allocated, that means it's safe to not declare
an allocator to use for those. For example, the base TypedArray<T>,
which is never directly allocated and only the defined specializations
are ever allocated.
2026-01-20 12:00:11 +01:00

34 lines
824 B
C++

/*
* Copyright (c) 2020, Matthew Olsson <mattco@serenityos.org>
*
* SPDX-License-Identifier: BSD-2-Clause
*/
#pragma once
#include <LibWeb/Layout/BlockContainer.h>
#include <LibWeb/SVG/SVGElement.h>
#include <LibWeb/SVG/SVGGraphicsElement.h>
namespace Web::Layout {
class SVGBox : public Box {
GC_CELL(SVGBox, Box);
GC_DECLARE_ALLOCATOR(SVGBox);
public:
SVGBox(DOM::Document&, SVG::SVGElement&, GC::Ref<CSS::ComputedProperties>);
virtual ~SVGBox() override = default;
SVG::SVGElement& dom_node() { return as<SVG::SVGElement>(*Box::dom_node()); }
SVG::SVGElement const& dom_node() const { return as<SVG::SVGElement>(*Box::dom_node()); }
private:
virtual bool is_svg_box() const final { return true; }
};
template<>
inline bool Node::fast_is<SVGBox>() const { return is_svg_box(); }
}