mirror of
https://github.com/LadybirdBrowser/ladybird
synced 2026-04-27 18:17:22 +02:00
55ebd8a589
Treat structurally equivalent invalidation plans as equal even when their descendant or sibling rules were accumulated in a different order. This lets :has() invalidation merge more of the repeated descendant-only payloads that still showed up after the earlier structural dedup. Add a :has() invalidation counter test that exercises equivalent selector permutations so this shape stays covered.
29 lines
951 B
HTML
29 lines
951 B
HTML
<!DOCTYPE html>
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<script src="../include.js"></script>
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<script src="_helpers.js"></script>
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<style>
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.anchor:has(:is(.outer-a, .outer-b) :is(.inner-a, .inner-b) .leaf) { color: red; }
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.anchor:has(:is(.outer-b, .outer-a) :is(.inner-b, .inner-a) .leaf) { color: red; }
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.anchor:has(:is(.outer-a, .outer-b) :is(.inner-b, .inner-a) .leaf) { color: red; }
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.anchor:has(:is(.outer-b, .outer-a) :is(.inner-a, .inner-b) .leaf) { color: red; }
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</style>
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<div class="anchor" id="anchor">
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<div class="outer-a" id="outer">
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<div class="inner-b" id="inner">
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<span id="target">leaf</span>
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</div>
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</div>
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</div>
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<script>
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test(() => {
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let anchor = document.getElementById("anchor");
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let target = document.getElementById("target");
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settleAndReset(anchor);
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target.classList.add("leaf");
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getComputedStyle(anchor).color;
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printCounters("after add .leaf");
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});
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</script>
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